Math Portal Home > Daily Dilemmas > Answer Key #15 
Daily Dilemma #15: Answer Key
morning

1

2

3

4

5

6

no. of pioneers

1

6

11

16

21

26

morning

7

8

9

10

11

12

no. of pioneers

31

36

41

46

51

56

On the 12th morning, there were 56 pioneers.
Rule: no. of pioneers = 5 • no. of mornings – 4
Extra Credit: Together, the
Morris, Jones, Baker, Brown, and Welch wagons have
5 • 5 = 25 chickens. This is half of the total number of chickens.
So, there are 25 • 2 = 50 chickens
Math Portal Home > Daily Dilemmas > Answer Key #15 