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Daily Dilemma #15: Answer Key
morning
|
1
|
2
|
3
|
4
|
5
|
6
|
no. of pioneers
|
1
|
6
|
11
|
16
|
21
|
26
|
morning
|
7
|
8
|
9
|
10
|
11
|
12
|
no. of pioneers
|
31
|
36
|
41
|
46
|
51
|
56
|
On the 12th morning, there were 56 pioneers.
Rule: no. of pioneers = 5 no. of mornings 4
Extra Credit: Together, the
Morris, Jones, Baker, Brown, and Welch wagons have
5 5 = 25 chickens. This is half of the total number of chickens.
So, there are 25 2 = 50 chickens
Math Portal Home > Daily Dilemmas > Answer Key #15 |